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NTA announces 87.89 as cut-off score for JEE Advanced 2021



Students who achieved a score of above 87.89 in the Joint Entrance Examination (JEE-Main) will be eligible for JEE (Advanced), the entrance test for admission to IITs, according to the cut-offs announced by the National Testing Agency (NTA). A total of 2.5 lakh candidates from JEE (Main) have qualified for the JEE (Advanced). The qualifying percentile for unreserved category is 87.9 this year as against 89.7 in 2019, while for the OBC, it is 68 as against 74.3 in 2019. This year, a total of 44 students have scored 100 percentile and 18 candidates have shared the AIR 1.